Given: Equation of line is

_{Equation of plane is x – y + z = 0}

To find: Angle between a line and the normal to a plane.

Formula Used: If θ is the angle between two lines with direction ratios b₁:b₂:b₃ and c₁:c₂:c₃, then

Explanation:

Direction ratios of given line is 1 : 2 : 1

Direction ratios of the normal to the plane is 1 : -1 : 1

Therefore,

cos θ = 0

θ = 90°

Therefore angle between them is 90°