Mark against the correct answer in each of the following:
The distance between the parallel planes 2x – 3y + 6z = 5 and 6x – 9y + 18z + 20 = 0, is
Given: The equations of the parallel planes are 2x – 3y + 6z = 5 and 6x – 9y + 18z + 20 = 0
To find: distance between the planes
Formula Used: Distance between two parallel planes ax + by + cz + d1 = 0 and ax1 + by1 + cz1 + d1 = 0 is
Explanation:
The equations of the parallel planes are:
2x – 3y + 6z – 5 = 0
Therefore distance between them is
Therefore distance between the planes is units