Find the distance of the point (2, 1, - 1) from the plane x – 2y + 4z = 9.


Formula :


where () is point from which distance is to be calculated


Therefore ,


x - 2y + 4z = 9


x - 2y + 4z – 9 = 0


Point = ( 2 , 1 , - 1 )


Distance





1