Show that the point (1, 2, 1) is equidistant from the planes and


Formula :


where () is point from which distance is to be calculated


Therefore ,


First Plane can be written in cartesian form as


x + 2y - 2z = 5


x + 2y - 2z – 5 = 0


Point = ( 1 , 2 , 1 )


Distance for first plane





Second Plane can be written in cartesian form as


2x - 2y + z + 3 = 0


Point = ( 1 , 2 , 1 )


Distance for second plane





Hence proved.


1