Show that the planes 2x – y + 6z = 5 and 5x – 2.5y + 15z = 12 are parallel.


Formula : Plane = r . (n) = d


Where r = any random point


n = normal vector of plane


d = distance of plane from origin


If two planes are parallel , then their normal vectors are either same or proportional to each other


Therefore ,


Plane 1 : - 2x – y + 6z = 5


Normal vector (Plane 1) = (2i – j + 6k) …..(1)


Plane 2 : - 5x – 2.5y + 15z = 12


Normal vector (Plane 2) = (5i – 2.5j + 15k) …..(2)


Multiply equation(1) by 5 and equation(2) by 2


Normal vector (Plane 1) = 5(2i – j + 6k)


= 10i – 5j + 30k


Normal vector (Plane 2) = 2(5i – 2.5j + 15k)


= 10i – 5j + 30k


Since, both normal vectors are same .Therefore both planes are parallel


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