Find the distance between the planes x + 2y + 3z + 7 = 0 and 2x + 4y + 6z + 7 = 0.
Formula : The distance between two parallel planes, say
Plane 1:ax + by + cz + d1 = 0 &
Plane 2:ax + by + cz + d2 = 0 is given by the formula
where () are constants of the planes
Therefore ,
First Plane x + 2y + 3z + 7 = 0
2(x + 2y + 3z + 7) = 0
2x + 4y + 6z + 14 = 0 …… (1)
Second plane 2x + 4y + 6z + 7 = 0 …… (2)
Using equation (1) and (2)
Distance between both planes