If E1 and E2 are independent events such that P(E1) = 0.3 and P(E2) = 0.4, find
(i) P(E1∩ E2)
(ii) P(E1∩ E2)
(iii) 
(iv) 
Given: E1 and E2 are two independent events such that P(E1) = 0.3 and P(E2) = 0.4
To Find: i)P(E1
E2)
We know that,
when E1 and E2 are independent ,
P(E1
E2) = P(E1) 
P(E2)
= 0.3 
0.4
= 0.12
Therefore, P(E1
E2) = 0.12 when E1 and E2 are independent.
ii) P(E1
E2) when E1 and E2 are independent.
We know that,
Hence, P(E1
E2) = P(E1) + P(E2) - P(E1
E2)
= 0.3 + 0.4 – (0.3 
0.4)
= 0.58
Therefore , P(E1
E2) = 0.58 when E1 and E2 are Independent.
iii) P( 
) = P( 
) 
P( 
)
since , P(E1) = 0.3 and P(E2) = 0.4
P( 
) = 1 - P(E1) = 0.7 and P( 
) = 1 - P(E2) = 0.6
Since, E1 and E2 are two independent events
and 
are also independent events.
Therefore, P( 
) = 0.7 
0.6 = 0.42
iv) P( 
E2) = P( 
) 
P(E2)
= 0.7 
0.4
= 0.28
Therefore , P( 
E2) = 0.28