Mark (√) against the correct answer in each of the following:
Two numbers are selected random from integers 1 through 9. If the sum if even, what is the probability that both numbers are odd?
The sum will be even when; both numbers are either even or odd,
i.e. for both numbers to be even, the total cases 5C1X4C1 (Both the numbers are odd)+4C1X3C1 (Both the numbers are even)= 32
The favourable number of cases will be,
Both odd, i.e. selecting numbers from 1, 3, 5, 7, or 9, i.e.
5C1X4C1 = 20
Thus, the probability that both numbers are odd will be =
=
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