Mark (√) against the correct answer in each of the following:

Two numbers are selected random from integers 1 through 9. If the sum if even, what is the probability that both numbers are odd?


The sum will be even when; both numbers are either even or odd,


i.e. for both numbers to be even, the total cases 5C1X4C1 (Both the numbers are odd)+4C1X3C1 (Both the numbers are even)= 32


The favourable number of cases will be,


Both odd, i.e. selecting numbers from 1, 3, 5, 7, or 9, i.e.


5C1X4C1 = 20


Thus, the probability that both numbers are odd will be =


=


1