Mark (√) against the correct answer in each of the following:
A die is thrown 5 times. If getting an odd number is a success, then what is the probability of getting at least 4 successes?
Using Bernoulli’s Trial P(Success=x) = nCx.px.q(n-x)
x=0, 1, 2, ………n and q = (1-p)
As the die is thrown 5 times the total number of outcomes will be 
.
And we know that the favourable outcomes of getting at least 4 successes will be, either getting 1, 3 or 5 i.e., 1/6 probability of each, total, 
probability, p = 
,q = 
The probability of success is 
and of failure is also 
the probability of getting at least 4 successes =
P(4)+P(5)
⇒ 5C4(
)4(
)1 +5C5(
)5(
)0
⇒ 
1