Using Bernoulli’s Trial P(Success=x) = ⁿC_x.p^x.q^(n-x)

x=0, 1, 2, ………n and q = (1-p), here n = 7

As we know that the favourable outcomes of getting at most 6 success are, successes will be, getting a total of 7 is success, i.e.,

We can get 7 by, (1,6), (2,5), (3,4), (4,3), (5,2), (6,1)

, p = ,q =

The probability of success is and of failure is also

the probability of getting at most 6 successes =

P(0)+P(1)+P(2)+P(3)+P(4)+P(5)+P(6) = 1-P(7)

⇒ 1 – ⁷C₇()⁷()⁰

⇒ 1 - ()⁷