10 coins are tossed simultaneously. Find the probability of getting

(i) exactly 3 heads


(ii) not more than 4 heads


(iii) at least 4 heads


(i) As 10 coins are tossed simultaneously the total number of outcomes are =1024.


the favourable outcomes of getting exactly 3 heads will be


10C3 = 120


Thus, the probability





Hence, the probability is .


(ii) As 10 coins are tossed simultaneously the total number of outcomes are =1024.


the favourable outcomes of getting not more than 4 heads will be


10C0 + 10C1 + 10C2 + 10C3 + 10C4 = 386


Thus, the probability




⇒


Hence, the probability is .


(iii) As 10 coins are tossed simultaneously the total number of outcomes are =1024.


the favourable outcomes of getting at least 4 heads will be


10C4 + 10C5 + 10C6 + 10C7 + 10C8 + 10C9 + 10C10 = 848


Thus, the probability




⇒


Hence, the probability is .


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