There are 6% defective items in a large bulk of times. Find the probability that a sample of 8 items will include not more than one detective item.
Using Bernoulli’s Trial P(Success=x) = nCx.px.q(n-x)
x=0, 1, 2, ………n and q = (1-p), n =8
The probability of success, i.e. the bulb is defective = p = 
q = 
probability of that there is not more than one defective piece=
P(0 defective items) + P(1 defective item) =
8C0.(
)0(
)8 + 8C1.(
)1(
)7
⇒ (
7
)
1