The mean and variance of a binomial distribution are 4 and (4/3) respectively. Find P(X≥ 1).
Mean = np = 4
Variance = npq = 4/3
⇒ q = 
⇒ p = 1 - 
= 
⇒ n = 6
The probability (X
) is
6C1(
)1(
)5 + 6C1(
)1(
)5 + 6C1(
)1(
)5 + 6C1(
)1(
)5 + 6C1(
)1(
)5 + 6C1(
)1(
)5
= 
1