Find the adjoint of the given matrix and verify in each case that A. (adj A) = (adj A) =m |A|.I.


Here,


Now, we have to find adj A, and for that, we have to find co-factors:











[cos2 α + sin2 α = 1]



Calculating A (adj A)






[cos2 α + sin2 α = 1]



= I


Calculating (adj A)A






[cos2 α + sin2 α = 1]



= I


Calculating |A|.I


Expanding along C1, we get




= [0 – 0 + 1(cos2 α – (-sin2 α))]I


= [cos2 α + sin2 α] I


= (1)I [cos2 α + sin2 α = 1]


= I


Thus, A(adj A) = (adj A)A = |A|I = I


A(adj A) = (adj A)A = |A|I


Hence Proved


Ans.


1