Given y - 2≤3x

⇒ y≤3x + 2

Consider the equation y = 3x + 2

Finding points on the coordinate axes:

If x = 0, the y value is 2 i.e, y = 2

⇒ the point on Y axis is A(0,2)

If y = 0, 0 = 3x + 2

⇒x =

The point on the X axis is B( - ,0)

Plotting the points on the graph: fig. 6a

Now consider the inequality y≤3x + 2

Here we need the y value less than or equal to 3x + 2

⇒ the required region is below point A.

Therefore the graph of the inequation y≤3x + 2 is fig. 5b

Fig 6a

Fig 6b