Solve each of the following systems of simultaneous inequations:

3x + 4y 12, x 0, y 1 and 4x + 7y28


Consider the inequation 3x + 4y 12 :


⇒4y ≥ 12 - 3x


y 3 -


Consider the equation y = 3 -


Finding points on the coordinate axes:


If x = 0, the y value is 3 i.e, y = 3


the point on the Y axis is A(0,3)


If y = 0, 0 = 3 -


x = 4


The point on the X axis is B(4,0)


Now consider the inequality y 3 -


Here we need the y value greater than or equal to y 3 -


the required region is above point A.


Therefore the graph of the inequation y 3 - is fig. 9a



Fig 9a


Consider the inequation 4x + 7y28


7y28 - 4x


y≤4 -


Consider the equation y = 4 -


Finding points on the coordinate axes:


If x = 0, the y value is 4 i.e, y = 4


the point on the Y axis is C(0,4)


If y = 0, 0 = 4 -


x = 7


The point on the X axis is D(7,0)


Now consider the inequality y≤4 -


Here we need the y value less than or equal to 4 -


the required region is below point C.


Therefore the graph of the inequation y≤4 - is fig. 9b



Fig 9b


x 0 is the region right side of Y - axis.


y 1 is the region above the line y = 1


Combining all the above results in a single graph , we’ll get



The solution of the system of simultaneous inequations is the intersection region of the solutions of the two given inequations.


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