Find the particular solution of the different equation.2xy + y2 - 2x2 = 0, it being given that y = 2 when x = 1
2xy + y2 - 2x2 = 0
⇒ the given differential equation is a homogenous equation.
The solution of the given differential equation is :
Put y = vx
Integrating both the sides we get:
Resubstituting the value of y = vx we get
Now,
y = 2 when x = 1
Ans: