Find the particular solution of the differential equation given that y = 1 when x = 1.
⇒ the given differential equation is a homogenous equation.
The solution of the given differential equation is :
Put y = vx
⇒
Integrating both the sides we get:
Resubstituting the value of y = vx we get
y = 1 when x = 1
1 + 0 = - 0 + c
⇒ c = 1
⇒ = 1
Ans: = 1