Find the particular solution of the differential equation
given that y = 1 when x = 1.
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⇒ the given differential equation is a homogenous equation.
The solution of the given differential equation is :
Put y = vx
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Integrating both the sides we get:
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Resubstituting the value of y = vx we get

y = 1 when x = 1
1 + 0 = - 0 + c
⇒ c = 1
⇒
= 1
Ans:
= 1