find the approximate values of log 10 (4.04), it being given that log 10 4 = 0.6021 and log 10 e = 0.4343

Question

Philoid · Accepted Answer

Let

∴

Let x =4 and Δx = 0.04.

As

⇒

We, know

⇒

∴

⇒

∴ Δy = 0.004343

Also,

Δy = f(x+Δx)-f(x)

∴ 0.004343 = log_e(4+0.04) – log_e(4)

⇒ 0.004343 = log_e(4.04) – 0.6021

⇒ log_e(4.04) = 0.606443.