Find the points on the curve , where the tangent to the curve is parallel to the chord joining (1, 2) and (2, 2).

Given:


y=x3-3x


Since y is a polynomial function.


It is continuous and differentiable in [1,2]


So, there exists a c such that:




=4


f' (c)=3c2-3


3 c2-3=4


3c2=7




So, the points are


1