Show that has a maximum and minimum, but the maximum value is less than the minimum value.
F(x)=x+
Taking first derivative and equating it to zero to find extreme points.
F’(x)=1-
X2=1
x=1,x=-1
now to determine which of these is min. And max. We use second derivative.
f||(x)=
f||(1)=2 and f||(-1)=-2
since f||(1) is +ve it is minimum point while f||(-1) is –ve it is maximum point
max value-> f(-1)=-1+=-2
min vaue-> f(1)=1+=2
hence maximum value is less than minimum value