Find the intervals on which the function is
(a) strictly increasing
(b) strictly decreasing.
f(x)=(2x2-3x)
f’(x)=4x-3
f’(x)=0 at x=3/4
Clearly we can see that function is increasing for x∈[3/4, ∞) and is decreasing for x∈(-∞,3/4)