Find two positive number whose product is 49 and the sum is minimum.

Given,


The two numbers are positive.


the product of two numbers is 49.


the sum of the two numbers is minimum.


Let us consider,


x and y are the two numbers, such that x > 0 and y > 0


Product of the numbers : x × y = 49


Sum of the numbers : S = x + y


Now as,


x × y = 49


------ (1)


Consider,


S = x + y


By substituting (1), we have


------ (2)


For finding the maximum/ minimum of given function, we can find it by differentiating it with x and then equating it to zero. This is because if the function f(x) has a maximum/minimum at a point c then f’(c) = 0.


Differentiating the equation (2) with x




----- (3)


[Since and ]


Now equating the first derivative to zero will give the critical point c.


So,





= x2 = 49



As x > 0, then x = 7


Now, for checking if the value of S is maximum or minimum at x=7, we will perform the second differentiation and check the value of at the critical value x = 7.


Performing the second differentiation on the equation (3) with respect to x.





[Since and ]



Now when x = 7,



As second differential is positive, hence the critical point x = 7 will be the minimum point of the function S.


Therefore, the function S = sum of the two numbers is minimum at x = 7.


From Equation (1), if x= 7



Therefore, x = 7 and y = 7 are the two positive numbers whose product is 49 and the sum is minimum.


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