Show that the height of a closed cylinder of given volume and the least surface area is equal to its diameter.
Let r be the radius of the base and h the height of a cylinder.
The surface area is given by,
S = 2 π r2 + 2 π rh
………(1)
Let V be the volume of the cylinder.
Therefore, V = πr2h
…….Using equation 1
Differentiating both sides w.r.t r, we get,
……….(2)
For maximum or minimum, we have,
⇒
⇒ S = 6πr2
2πr2 + 2πrh = 6πr2
h = 2r
Differentiating equation 2, with respect to r to check for maxima and minima, we get,
Hence, V is maximum when h = 2r or h = diameter