Find the equations of the tangent and the normal to the given curve at the indicated point for

at the point where x = 1



m at (x = 1) = 2


y at (x = 1) = (1)4 – 6(1)3 + 13(1)2 – 10(1) + 5 = 3


Tangent : y – b = m(x – a)


y – 3 = 2(x – 1)


2x – y + 1 = 0


Normal :



x + 2y – 7 = 0


1