Mark (√) against the correct answer in the following:
The maximum value of 
is
⇒ 
∴ 
⇒ f’(x) = log x – 1
⇒ Put f’(x) = 0
We get x =e
F’’(x) = 1/x
Put x =e in f’’(X)
1/e is point of maxima
∴ The max value is 1/e.
1
Mark (√) against the correct answer in the following:
The maximum value of is
⇒
∴
⇒ f’(x) = log x – 1
⇒ Put f’(x) = 0
We get x =e
F’’(x) = 1/x
Put x =e in f’’(X)
1/e is point of maxima
∴ The max value is 1/e.