Mark (√) against the correct answer in the following:

The minimum value of on [0, 3] is


Given:


f(x) = 3x4-8x3-48x+25.


F’(x) = 12x3-24x2-48 = 0


F’(x) = 12(x3-2x2-4) = 0


Differentiating again, we get,


F’’(x) = 3x2 – 4x = 0


x(3x – 4) = 0


x = 0 or x = 4/3


Putting the value in equation, we get,


f(x) = -39


Hence, C is the correct answer.

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