Draw a triangle ABC with side BC = 6 cm, AB=5 cm and ∠ABC=60°. Then construct a triangle whose sides are of the corresponding sides of the triangle ABC.
△A′BC′ whose sides of the corresponding sides of can be drawn as follows.
Step 1 Draw a △ABC with side BC = 6 cm, AB = 5 cm and ∠ABC = .
Step 2 Draw a ray BX making an acute angle with BC on the opposite side of vertex A.
Step 3 Locate 4 points (as 4 is greater in 3 and 4), B1,B2,B3,B4 on line segment BX.
Step 4 Join B4C and draw a line through B3 , parallel to B4C intersecting BC at C′
Step 5 Draw a line through C' parallel to AC intersecting AB at A'.△A′BC′ is the required triangle.
Justification
∠A=60° (Common)
∠C=∠C'
By AA similarity condition
Also,
AB’=AB ,B’C’=BC and AC’=AC