Evaluate each of the following integrals as the limit of sums:


Since it is modulus function so we need to break the function and then solve it



it is continuous in [0,1]


let and



here h=1/3n









=1/3



here h=2/3n









=2/3


f(x)=g(x)+h(x)


=(1/3)+(2/3)


=3/3


=1


1