Find the area of the region bounded by the curve y2=4x and the lines x=3.
Given the boundaries of the area to be found are,
• The parabola y2 = 4x
• x = 3 (a line parallel toy-axis)
As per the given boundaries,
• The curve y2 =4x with vertex at (0,0), has only the positive numbers as y has even power, so it is about the x-axis equally distributed on both sides.
• x= 3 are parallel toy-axis at 3 units from the y-axis.
• The boundaries of the region to be found are,
•Point A, where the curve y2 = 4x and x=3 meet when y is positive.
•Point B, where the curve y2 = 4x and x=3 meet when y is negative.
•Point C, where the x-axis and x=3 meet i.e. C(3,0).
•Point O, the origin.
Area of the required region = Area of OAB
Area of OAB = Area of OAC + Area of OBC.
[area under OAC = area under OBC as the curve y2 = 4x is symmetric]
Area of OAB = 2 × Area of OAC
[Using the formula ]
The Area of the required region