Given the boundaries of the area to be found are,

• The curve y² = 4ax

• y = 2a (a line parallel to x-axis)

• x = 0 (y-axis)

As per the given boundaries,

• The curve y² =4ax, has only the positive numbers as y has even power, so it is about the x-axis equally distributed on both sides.

• y= 2a is parallel to x-axis with 2a units from the x-axis.

The boundaries of the region to be found are,

•Point A, where the curve y² = 4ax and y=2a meet i.e. A(2a,2a)

•Point B, where the curve y² = 4ax and y-axis meet i.e. B(0,2a)

•Point O, is the origin

Consider the curve y² = 4ax,

Area of the required region = Area of OBA.

[Using the formula ]

The Area of the required region