_Given

• Curve is

• x = 0 and

• x = π

The given curve is similar toy = sin² x.

Now consider the y values for some random x values between 0 and π for the function y = sin²x.

From the table we can clearly draw the graph for

The required area under the curve is given by:

[using the property cos 2x = 1- 2sin² x]

[using the formula, and ]

[as sin π = 0, then sin 2π = 0]

Hence the required area of the curve from x = 0 to x= π is sq. units.