Let ,

Putting

Which implies 2x=1 = A(x-3) + B(x+2)

Now put x-3=0, x=3

2×3+1=A(0 )+B 3+2)

So

Now put x+2=0 ,x=-2

-4+1=A(-2-3) + B(0)

So

From equation (1), we get ,