Evaluate:
Let
Putting
Which implies,
A(x-2)(x-4)+Bx(x-4)+Cx(x-2)=1
Now put x-2=0
Therefore, x=2
A(0)+B×2(2-4)+C(0)=1
B×2(-2)=1
Now put x-4=0
Therefore, x=4
A(0)+B×(0)+C×4(4-2)=1
C×4(2)=1
Now put x=0
A(0-2)(0-4)+B(0)+C(0)=1
Now From equation (1) we get