Evaluate:


Let


Which implies


Therefore, I=x+I1


Where, I1=


Putting


Which implies,


A(x+2)+B(x+1)=2x+1


Now put x+2=0


Therefore, x=-2


A(0)+B(-1)=-4+1


B=3


Now put x+1=0


Therefore, x=-1


A(-1+2)+B(0)=-2+1


A=-1


Now From equation (1) we get,





1