Evaluate:


Let






Put


A(x-1)+B(x+2)=5x+1


Now put x-1=0


Therefore, x=1


A(0)+B(1+2)=5+1=6


B=2


Now put x+2=0


Therefore, x=-2


A(-2-1)+B(0)=5×(-2)+1


A=3


Now From equation (1) we get,





Therefore,



1