Evaluate:


Let


Putting t=sin x


dt=cos x dx



Now putting,


A(2+t)+B(1+t)=1


Now put t+1=0


Therefore, t=-1


A(2-1)+B(0)=1


A=1


Now put t+2=0


Therefore, t=-2


A(0)+B(-2+1)=1


B=-1


Now From equation (1) we get,






So,



1