Evaluate:
Let
Now putting,
A(x-1)2+B(x+3)(x-1)+C(x+3)=x2+1
Now put x-1=0
Therefore, x=1
A(0)+B(0)+C(4) =2
Now put x+3=0
Therefore, x=-3
A(-3-1)2+B(0)+C(0) =9+1=10
By equating the coefficient of x2, we get, A+B=1
From equation (1), we get,