Evaluate:
Let
Now putting,
A(x-1)2+B(2x-3)(x-1)+C(2x-3) = 5x2-18x+17
Putting x-1=0,
X=1
A(0)+B(0)+C(2-3)=5-18+17
C(-1)=4
Putting 2x-3=0,
A=5
By equating the coefficient of x2, we get ,
A+2B=5
5+2B=5
2B=0
B=0
From equation (1), we get,