Find the direction cosines of the normal to the plane 2x + 3y - z = 4.
Given :
Equation of plane : 2x + 3y – z = 4
To Find : Direction cosines of the normal i.e.
Formula :
1) Direction cosines :
If a, b & c are direction ratios of the vector then its direction cosines are given by
Answer :
For the given equation of plane
2x + 3y – z = 4
Direction ratios of normal vector are (2, 3, -1)
Therefore, direction cosines are