Find the direction cosines of the normal to the plane 3x + 4 = 0.
Given :
Equation of plane : 3x + 4 = 0
To Find : Direction cosines of the normal i.e.
Formula :
1) Direction cosines :
If a, b & c are direction ratios of the vector then its direction cosines are given by
Answer :
For the given equation of plane
-3x = 4
Direction ratios of normal vector are (-3, 0, 0)
= 3
Therefore, direction cosines are