Given :

Point : (4, -2, 3)

To Find : equation of plane

Formula :

1) Equation of plane :

Equation of plane passing through point A with position vector and perpendicular to vector is given by,

Where,

Answer :

Position vector for given point A ≡ (4, -2, 3) is

As required plane is parallel to XY plane, therefore Z-axis is perpendicular to the plane.

Therefore, equation of plane is

This is required equation of plane.