Given :

Point : (-3, 2, 0)

To Find : equation of plane

Formula :

1) Equation of plane :

Equation of plane passing through point A with position vector and perpendicular to vector is given by,

Where,

Answer :

Position vector for given point A ≡ (-3, 2, 0) is

As required plane is parallel to YZ plane, therefore X-axis is perpendicular to the plane.

Therefore, equation of plane is

This is required equation of plane.