Given :

Equation of plane : 2x – 3y + 6z + 21 = 0

To Find :

Length of perpendicular drawn from origin to the plane = d

Formulae :

1) Distance of the plane from the origin :

Distance of the plane from the origin is given by,

Answer :

For the given equation of plane

2x – 3y + 6z = -21

Direction ratios of normal vector are (2, -3, 6)

Therefore, equation of normal vector is

= 7

From given equation of plane,

p = -21

Now, distance of the plane from the origin is

d = 3 units