Find the equation of the plane passing through each group of points:
(i) A(2, 2, -1), B(3, 4, 2) and C(7, 0, 6)
(ii) A(0, -1, -1), B(4, 5, 1) and C(3, 9, 4)
(iii) A(-2, 6, -6), B(-3, 10, 9) and
(i) A(2, 2, -1), B(3, 4, 2) and C(7, 0, 6)
Given Points :
A = (2, 2, -1)
B = (3, 4, 2)
C = (7, 0, 6)
To Find : Equation of plane passing through points A, B & C
Formulae :
1) Position vectors :
If A is a point having co-ordinates (a1, a2, a3), then its position vector is given by,
2) Vector :
If A and B be two points with position vectors respectively, where
then,
3) Cross Product :
If are two vectors
then,
4) Dot Product :
If are two vectors
then,
5) Equation of Plane :
If A = (a1, a2, a3), B = (b1, b2, b3), C = (c1, c2, c3) are three non-collinear points,
Then, the vector equation of the plane passing through these points is
Where,
For given points,
A = (2, 2, -1)
B = (3, 4, 2)
C = (7, 0, 6)
Position vectors are given by,
Now, vectors are
Therefore,
Now,
= 40 + 16 + 12
= 68
………eq(1)
And
= 20x + 8y – 12z
………eq(2)
Vector equation of the plane passing through points A, B & C is
From eq(1) and eq(2)
20x + 8y – 12z = 68
This is 5x + 2y – 3z = 17 vector equation of required plane.
(ii) Given Points :
A = (0, -1, -1)
B = (4, 5, 1)
C = (3, 9, 4)
To Find : Equation of plane passing through points A, B & C
Formulae :
1) Position vectors :
If A is a point having co-ordinates (a1, a2, a3), then its position vector is given by,
2) Vector :
If A and B be two points with position vectors respectively, where
then,
3) Cross Product :
If are two vectors
then,
4) Dot Product :
If are two vectors
then,
5) Equation of Plane :
If A = (a1, a2, a3), B = (b1, b2, b3), C = (c1, c2, c3) are three non-collinear points,
Then, vector equation of the plane passing through these points is
Where,
For given points,
A = (0, -1, -1)
B = (4, 5, 1)
C = (3, 9, 4)
Position vectors are given by,
Now, vectors are
Therefore,
Now,
= 0 + 14 – 22
= - 8
………eq(1)
And
= 10x - 14y + 22z
………eq(2)
Vector equation of plane passing through points A, B & C is
From eq(1) and eq(2)
10x - 14y + 22z = - 8
This is 5x - 7y + 11z = - 4 vector equation of required plane
(iii) Given Points :
A = (-2, 6, -6)
B = (-3, 10, 9)
C = (-5, 0, -6)
To Find : Equation of plane passing through points A, B & C
Formulae :
1) Position vectors :
If A is a point having co-ordinates (a1, a2, a3), then its position vector is given by,
2) Vector :
If A and B be two points with position vectors respectively, where
then,
3) Cross Product :
If are two vectors
then,
4) Dot Product :
If are two vectors
then,
5) Equation of Plane :
If A = (a1, a2, a3), B = (b1, b2, b3), C = (c1, c2, c3) are three non-collinear points,
Then, vector equation of the plane passing through these points is
Where,
For given points,
A = (-2, 6, -6)
B = (-3, 10, 9)
C = (-5, 0, -6)
Position vectors are given by,
Now, vectors are
Therefore,
Now,
= - 180 - 270 – 108
= - 558
………eq(1)
And
= 90x - 45y + 18z
………eq(2)
Vector equation of plane passing through points A, B & C is
From eq(1) and eq(2)
90x - 45y + 18z = - 558
This is 10x - 5y + 2z = - 62 vector equation of required plane