Find the vector and Cartesian equations of a plane which is at a distance of 7 units from the origin and whose normal vector from the origin is
Given :
d = 7
To Find : Equation of plane
Formulae :
1) Unit Vector :
Let be any vector
Then unit vector of is
Where,
2) Dot Product :
If are two vectors
then,
3) Equation of plane :
Equation of plane which is at a distance of 5 units from the origin and having as a unit vector normal to it is
Where,
For given normal vector
Unit vector normal to the plane is
Equation of the plane is
This is a vector equation of the plane.
Now,
= (x × 3) + (y × 5) + (z × (-6))
= 3x + 5y – 6z
Therefore equation of the plane is
This is the Cartesian equation of the plane.