Given :

Equation of plane : 3x – 6y + 2z = 7

To Find : Direction cosines of the normal, i.e.

Formula :

1) Direction cosines :

If a, b & c are direction ratios of the vector, then its direction cosines are given by

For the given equation of a plane

3x – 6y + 2z = 7

Direction ratios of normal vector are (3, -6, 2)

Therefore, direction cosines are