A housewife wishes to mix together two kinds of food, X and Y, in such a way that the mixture contains at least 10 units of vitamin A, 12 units of vitamin B and 8 units of vitamin C.

The vitamin contents of 1 kg of each food are given below.



If 1 kg of food X cost ₹6 and 1 kg of food Y costs ₹10, find the minimum cost of the mixture which will produce the diet.



Let x and y be number of kilograms of food X and Y.


∴According to the question,


x + 2y , 2x + 2y


Minimize Z = 6x + 10y


The feasible region determined x + 2y , 2x + 2y is given by



The feasible region is unbounded. The corner points of feasible region are A(0,8) , B(1,5) , C(2,4) , D(10,0).The value of Z at corner points are



The minimum value of Z is 52 at point (2,4).


Hence, the diet should contain 2 kgs of food X and 4 kgs of food Y for the least cost of Rs. 52.


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