Equal masses of air are sealed in two vessels, one of volume V 0 and the other of volume 2V 0 . If the first vessel is maintained at a temperature 300 K and the other at 600 K, find the ratio of the pressures in the two vessels.

Question

Philoid · Accepted Answer

We know ideal gas equation

PV=nRT

Where V= volume of gas

R=gas constant

T=temperature

n=number of moles of gas

P=pressure of gas.

Given

Masses of both the gas is equal. Therefore, number of moles of both the gas is equal. So, we can write

n₁ =n₂ =n

Volume of first gas V₁=V_o

Volume of second gas V₂=2V_o

Temperature of first gas T₁=300K

Temperature of second gas T₂=600K

Let pressure of first gas =P₁

Pressure of second gas=P₂

Applying ideal gas equation for both the gases

P₁V₁=n₁RT₁

…(I)

P₂V₂=n₂RT₂

…. (II)

Since n₁ =n₂ =n

Therefore

Rearranging the above equation

P₁:P₂ =1:1

So, the ratio of pressure gas in two vessels is 1:1.

Equal masses of air are sealed in two vessels, one of volume V0 and the other of volume 2V0. If the first vessel is maintained at a temperature 300 K and the other at 600 K, find the ratio of the pressures in the two vessels.

Equal masses of air are sealed in two vessels, one of volume V₀ and the other of volume 2V₀. If the first vessel is maintained at a temperature 300 K and the other at 600 K, find the ratio of the pressures in the two vessels.