Find the rms speed of hydrogen molecules in a sample of hydrogen gas at 300 K. Find the temperature at which the rms speed is double the speed calculated in the previous part.
We know that rms speed of gas is given by
Where R=gas constant 8.31J/molK
T=temperature of gas
M=molar mass of gas
Given
Temperature T=300K
Molar mass of hydrogen=2g/mol
Therefore,
Now in second part of question speed is doubled i.e. 21932.6ms-1
Let temperature at this speed be T1
So, using the same formula of rms speed
Squaring both sides of above equation
Temperature of the gas when speed is doubled is 1200K which is 4 times the pervious temperature.